Projectile Motion

A particle is projected in the X-Y plane. $2 \mathrm{s}$ after projection, the velocity of the particle makes an angle $45°$ with the X-axis. $4 \mathrm{s}$ after projection, it moves horizontally. Find the velocity of projection (use $\mathrm{g} = 10 \mathrm{m} {\mathrm{s}}^{-2}$)

The maximum range of a gun of horizontal terrain is $16 \mathrm{km}$. If $g=10\mathrm{m}{\mathrm{s}}^{-2},$ then, muzzle velocity of a shell must be

The direction of projection of particle is shown in the figure for an observer on trolley. An observer on the ground sees the ball rise vertically. The maximum height reached by ball as seen from the trolley is

The relation between the time of flight of a projectile $T$, and the time to reach the maximum height, $t$​ is

A projectile is projected with a velocity $v$ making an angle with horizontal, the equation for time of flight is

A ball is projected horizontally from a certain height with a velocity of $2 \text{m/s}$. Determine the time required by it to reach its maximum height.

For an object thrown at $45°$ to horizontal, the maximum height $H$ and horizontal range $R$ are related as :

The horizontal range of a projectile is added maximum for a given velocity of projection when the angle of projection is :

 An aeroplane flying 490 m above ground level at 100 m/s, releases a block. How far on the ground will the block strike? (take $g=9.8 m{s}^{-2}$)

A food packet is dropped from an aeroplane moving horizontally at a constant speed. When air resistance is taken into consideration, the food packet will

A particle is dropped from the same height when another particle is thrown horizontally. Both the particles will hit the ground: 

The moon is 4×10^8 m from earth.a radar signal transmitte from earth will reacheto the moon about.

A particle moves along the x-axis according to the equation$x = 6t^2$ where x is displacement in meters and t is time in seconds. Therefore
$1. the acceleration of the particle is 6 m{s}^{-2}.$
$2. the particle follows a parabolic path$
$3. each second the velocity of the particle change by 12 m{s}^{-1}.$
$4. the velocity of the particle is 6 m{s}^{-1}.$

Velocity ( v) - time (t) graph of a body is shown
in figure.

It implies that at point Q

Two bullets are fired horizontally with different velocities from the same height. Which one will reach the ground first?

At the top of the trajectory of a projectile, the acceleration is

It is given that a projectile is fired horizontally with a velocity of $98 {\mathrm{ms}}^{-1}$ from the top of a mountain $490 \mathrm{m}$ high. Calculate the velocity of the projectile by which it strikes the ground. $\left(\mathrm{g}=9.8 {\mathrm{ms}}^{-2}\right)$

The time of flight of projectile is $10$ second and its range is $500\mathrm{m}.$ The maximum height reached by it is $\left(\mathrm{g}=10{\mathrm{ms}}^{-2}\right)$